I recently found this question:
It is closed as a duplicate of our reference question for regular languages. However, in my (and Apass.Jack's) opinion, it is not a duplicate. Basically, the solution includes two parts:
Show the language is equivalent to $\{a^t\mid t\ge 1\}$ (or $\ge 2$, whatever).
Show $\{a^t\mid t\ge 1\}$ is regular.
Obviously, Part 1 is the (relatively) tricky part (we can see in the comment that OP is indeed confused with this part), while our reference question only deals with Part 2.
Of course, this question itself may not be a good question. First, it may be too simple, and second, the OP shows no effort. However, neither should be a close reason:
- For the "too simple" issue, see Introduce a "general reference" close reason.
- For the "no effort" issue, see Should we have a close reason "shows too little effort"?.
We can downvote this question because of these issues, but I don't see any reason to close it.
So should this question really be closed?
BTW, this question has ever been voted to reopen, but only one other user agrees with me.